A current of 2 ampere produces 200 joule of heat in a wire in a given period of time of the currents in case of 4 ampere how much it will it produce in the same time
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Answer:
I = 2A
H = 200 J
Let resistance br R ohm and time for which current flows be t seconds
H = I^2 R t
or 200 = 2 *2* R*t
or R*t = 200/2= 100..........1
now, new current l'= 4A
H'= (l')^2*R*t. ( as resistance and time are constant)
or H'= 4*4*100 ( from 1)
or H'= 1600 J
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