A current of 200mA flows through a 4komega resistor. what is the P.d. across it.
Answers
Answered by
1
Answer:
P.D = IR = 200 * 10^-3 * 4 * 10^3 = 800 volts
Potential difference across the resistor is 800 volts
Explanation:
Answered by
6
Current(I) = 200 mA or 200 × 10^-3
Resistance(r) = 4k ohms or 4 × 10^3
Potential difference =?
Ohm's law:
V = IR
V = 200 × 10^-3 × 4 × 10^3
V = 800 volts
Hence potential difference across the resistor = 800 volts.
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