Science, asked by msaw2914, 14 days ago

A current of 200mA flows through a 4komega resistor. what is the P.d. across it.​

Answers

Answered by Arn4vOP
1

Answer:

P.D = IR = 200 * 10^-3 * 4 * 10^3 = 800 volts

Potential difference across the resistor is 800 volts

Explanation:

Answered by Anonymous
6

Current(I) = 200 mA or 200 × 10^-3

Resistance(r) = 4k ohms or 4 × 10^3

Potential difference =?

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Ohm's law:

V = IR

V = 200 × 10^-3 × 4 × 10^3

V = 800 volts

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Hence potential difference across the resistor = 800 volts.

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