Question

A current of 2A flows through a wire for a minute. Find the amount of charge flown through the wire? If the wire is connected in series to a 9V battery, how much energy would be spend by the battery?

Answer 1

Answer:

Given,

Current in 2Ω resister = 3A

Potential across 2Ω resister V= IR=3×2=6V

Potential is equal in parallel connection.

Current flow in 1Ω & 5Ω resister i=

R

V

=

5+1

6

=1A

Power dissipate in 5Ω resister =i

2

R=1

2

×5=5 W

Power dissipate in 5Ω resister is 5W