Question

A current of 2A flows trough a conductor whose ends are at a p.d of 4V.The resistance of the conductor is :

 8 Ω

0.5 Ω

6 Ω

2 Ω

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Answer 1

Answer:

here is your right answer

Explanation:

we know that V=IR

R=V/I

R=4/2=2ohm