a current of 2A is passed through a coil of resistance 75 ohm for 2 min. how much heat energy is passed?
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Answered by
37
the enrgy passed is 36000J
as h =i2rt
derefor i =2 A
r=75 ohm
t=2 min = 2×60 =120 s
now putting values ans ll b 36000J
as h =i2rt
derefor i =2 A
r=75 ohm
t=2 min = 2×60 =120 s
now putting values ans ll b 36000J
Answered by
23
so here is your answer
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