Question

A current of 3.2 A is drawn by filament of an electric bulb. What is the number of electrons passing through the cross-section of the filament in 1 minute.​

Answer 1

Explanation:

Correct option is

A

10

20

Given : I=1A,t=16s,e=1.6×10

−19

C

Step 1: Current drawn by the filament

I=

t

Q

=

t

Ne

(Since Q=Ne, where N is the number of electrons crossing in time t)

⇒N=

e

I t

....(1)

Step 2: Substituting the values in equation (1)

N=

e

I t

=

1.6×10

−19

C

1A×16s

=10

20

Hence, number of electrons passing through a cross section of the filament in 16 seconds would be 10

20

.

Answer 2

Explanation:

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