A current of 3.2 mA is flowing through a
conductor, then number of free electrons
moving per sec is:
1) 2* 1019
2) 2 * 1016
3) 2* 1018
4) 2* 1017
hint=the digit after 10 is in the power
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0
Answer:
b. 2*1016
option b is correct
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