Physics, asked by garvitjain311, 9 months ago

A current of 3.2 mA is flowing through a
conductor, then number of free electrons
moving per sec is:

1) 2* 1019
2) 2 * 1016
3) 2* 1018
4) 2* 1017
hint=the digit after 10 is in the power​

Answers

Answered by vanshmasandsingh
0

Answer:

b. 2*1016

option b is correct

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