Question

A current of 3.6 mA is flowing through the element of vacuum tube. How many electrons are flowing per second through the element? How much charge will pass in 10 minutes? Given that magnitude of charge on each electron is 1.6 x 10⁻¹⁹ C.

Answer 1

Answer:

2.237 x 10^16 electrons

2.1 C

Explanation:

We are given that charge on an electron is;

1 electron = (1.609 x 10^-19)C

Current = Charge/time

1 Amp= 1C/second

3.6 x 10^-3 Amp = 3.6 x 10^-3 C/second

Hence, number of electrons = 3.6 x 10^-3 /(1.609 x 10^-19)

Electrons = 2.237 x 10^16

Now to determine charge magnitude;

Q = I x t

Q = 3.6 x 10^-3 Amp  x 10 x 60 = 2.1C

Answer 2

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