Question

A current of 3 Ais flowing in a linear conductor having
a length of 40 cm. The conductor is placed in a
magnetic field of strength 500 gauss and makes an
angle of 30° with the direction of the field. It experience a force of magnitude:​

Answer 1

Answer:

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Answer 2

Answer:

The magnitude of force is $3\times10^{-2}\ N$.

Explanation:

Given that,

Current = 3 A

Length = 40 cm

Magnetic field = 500 Gauss

Angle = 30°

We need to calculate the force

Using formula of force

$F=Bil\sin\theta$

Put the value into the formula

$F=500\times10^{-4}\times3\times40\times10^{-2}\times\sin30$

$F=0.03\ N$

$F=3\times10^{-2}\ N$

Hence, The magnitude of force is $3\times10^{-2}\ N$.