Question

A current of 3A flows in a circuit shown in the figure. The potential difference between A and B is
1) 4V 2) 3V 3) 2V 4) 5V​

Answer 1

Answer:

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Explanation:

Resistance of the upper arm CAD=2Ω+3Ω=5Ω

Resistance of the lower arm CBD=3Ω+2Ω=5Ω

As the resistance of both arm are equal, therefore same amount of current flows in both the arms. Current through each arm. CAD or CBD=1A

Potential difference across C and A is VC−VA=(2Ω)(1A)=2V...(i)

Potential difference across C and B is VC−VB=(3Ω)(1A)=3V...(ii)

Substracting (i) from (ii), we get

VA−VB=3V−2V=1V

Answer 2

Answer:

Current passing through A=I[  5+10 5  ] =  3 /3

​  =1A

⇒ Through B = 2A

V  ab ​=6I  A ​ −2I  B ​   =6−4  

Vab =2V

Therefore the answer is  2v