A current of 4.4 amperes is following in a write. How many electrons pass a
given point in the wire in one second, if the charge on an electron is 1.6*10
coulomb?
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Answer:
Firstly the charge of an electron is 1.6×10^-9 C . So no. of electrons are 2.25×10^19.
Explanation:
Current flowing is 4.4 A and time is 1 sec. Charge of one electron is 1.6×10^-19 C . Let no. of electrons be n.
From the formula A = Q÷T
4.4=( 1.6 ×10^-19 ×n)÷1sec
4.4 ×1 = n × 1.6×10^-19
n = (4.4 × 10^19)÷1.6
n = 2.25 × 10^19.
Thank you.
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