Question

A current of 4A flows in a wire of resistance 60 ohm . Calculate electrical energy consumed in 2 minutes.

Answer 1

Answer

• Electrical Energy consumed in 2 minutes is 115.2 k-j

Question

• A current of 4 A flows in a wire of resistance 60 ohm

To Find

• Electrical energy consumed in 2 minutes

Solution

• We know that , " Energy is defined as the product of square of current and resistance and time "

⇒ Q = I²RT

Given energy is electrical energy .

⇒ Electrical Energy , E = I²RT

Given ,

Current , I = 4 A

Resistance , R = 60 Ω

Time , t = 2 min = 120 s

⇒ E = 4² * 60 * 120

⇒ E = 16 * 7200 A².Ω.s

⇒ E = 115.2 kilo-Joules

Answer 2

Answer:

clearly ,

I = 4 A

R = 60 ohm

t = 2 min = 2 * 60  = 120

hence ,

E =    $I^{2} Rt$

  = 16 * 7200

= 115 .2  KJ