A current of 4a is flowing through a 12v car headlight bulbs for 1/6 hours . how much energy transfer occurs during this time.
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P = VI
P = 4*12 = 48/100 Kw
Therefore,
E.E = P*t
= 48/100*1/6
= 0.08 KwH
P = 4*12 = 48/100 Kw
Therefore,
E.E = P*t
= 48/100*1/6
= 0.08 KwH
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