A current of 4Ampere flows through a bulb. How many electrons flow through the bulb in time of 2hours.
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Answer:
1.8*10^22electron
Explanation:
I=q/t
4A=ne/t
4*1=n*1.6*10^-19
4/1.6*10^-19=n
2.5*10^19=n
number of electron flow in 1second =2.5*10^19
nomber of electron flow in 2hrs =2.5610^19*2*3600(1hrs=3600second)
=18*10^21
=1.8*10^22
hope it helps you ♥️♥️
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