Question

a current of 5 A flow through a wire whose ends are at a potential difference of 3 v. calculate the resistance of wire.​

Answer 1

Given :

▪ Current flow through wire = 5A

▪ Applied pd = 3V

To Find :

▪ Resistance of wire.

Concept :

☞ This question is completely based on the concept of ohm's law.

☞ As per this law, Current passing through a conductor is directly proportional to the applied potential difference. ( At constant temperature)

Mathematically,

$\bigstar\:\underline{\boxed{\bf{\pink{V=I\times R}}}}$

where,

V denotes applies pd

I denotes flow of current

R denotes resistance

☞ Resistance of conductor depends on the length, area, material and also on temperature.

☞ SI unit : V/m or Ω

Calculation :

$\dashrightarrow\sf\:V=I\times R\\ \\ \dashrightarrow\sf\:3=5\times R\\ \\ \dashrightarrow\sf\:R=\dfrac{3}{5}\\ \\ \dashrightarrow\underline{\boxed{\bf{\purple{R=0.6\Omega}}}}\:\gray{\bigstar}$

Answer 2

$\huge\sf\pink{Answer}$

☞ Resistance = 0.6 $\sf\Omega$

$\rule{110}1$

$\huge\sf\blue{Given}$

✭ Current (I) = 5A

✭ Potential Difference (v) = 3V

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

◈ The resistance of the wire?

$\rule{110}1$

$\huge\sf\purple{Steps}$

Here we shall use he Ohm's Law,that is,

$\underline{\boxed{\green{\sf V=IR}}}$

Where,

$\quad$◕ V = Voltage

$\quad$◕ I = Current

$\quad$◕ R = Resistance

Substituting the given values,

➳ $\sf V=IR$

➳ $\sf 3=5\times R$

➳ $\sf\dfrac{3}{5} = R$

➳ $\sf\orange{R = 0.6 \ \Omega}$

$\rule{170}3$