Question

A current of 5 A flows in the winding of an electric motor, the resistance of
the winding being 100 Ω. Determine a) the p.d. across the winding and
b) the power dissipated in the coil.

Answer 1

P. D. =IR=5*100=500V
POWER =I*V=5*500=2500W
THANK YOU!