Question

A current of 5 ampere flow through each of two parallel long wire the wire 2.5 cm apart calculate force acting per unit length of each wire use the standard value of constant required what will be the nature of the force if both current flows in same direction

Answer 1

Explanation:

force= i1×i2×10^-7/r

=5^2×10^-7/2.5×10^-2

=1×10^-4 N

if current both will be in same direction then force will be in same direction

Answer 2

The force per unit length between them is 5×$10^{-6}$ N/m

Given:

A current of 5 ampere flow through each of two parallel long wire the wire 2.5 cm apart calculate force acting per unit length of each wire use the standard value of constant required

To Find:

What will be the nature of the force if both current flows in same direction

Solution:

From the above information we get,

I1 = I2 = 5A

d = 1m

Force per unit length between them    F = $\frac{mew0 I1 I2}{2pid}$

The Force is given as ,

F = $\frac{4pi(10^-7)(5)(5)}{2pi(1)}$

F = 5 × $10^{-6}$ N/m

Since current flows in the same direction in the wires, so the wires attract each other.

Hence, the force when they attract is F = 5 × $10^{-6}$ N/m

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