Question

a current of 5 ampere is flowing through a wire of 60 CM in length this wire is kept perpendicular to a uniform magnetic field of 20 Tesla calculate the value of force acting on this wire
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Answer 1

Answer:

A current of 5A is flowing through a wire of 60cm in length this wire is kept perpendicular to a uniform magnetic field of 20 Tesla calculate the value of force acting on this wire is $60N$

​Explanation:

When a wire that carries a current $I$ is placed in a magnetic field of intensity $B$ it will experience a magnetic force which is given by the formula

$F=qvBsin$θ

where $v$ is the velocity of charges, here $v=l/t$

so the force on the wire will be $F=q/tlBsin$θ$F=IlBsin$θ

since the wire is kept perpendicular to the field the angle will be $90$⁰

the  current flowing through the wire $I=5A$

length of the wire$l=60cm=0.60m$

the magnetic field intensity $B=20T$

substituting the given values the force acting on the wire is $F=5*0.60*20 sin90=60N$