Question

A current of 500mA flows in a series circuit containing an electric lamp and a conductor of 10ohm when connected to 6V battery. Find the resistance of the electric lamp.

Answer 1

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Answer 2

Resistance of the electric lamp= 2 ohm.

Given:

A current of 500 mA flows in a series circuit containing an electric lamp and a conductor of 10 ohm.

6V battery.

To find:

Resistance of the electric lamp.

Formula used:

Ohms law ⇒ V= $I\times R_{eq}$

Explanation:

From Ohms law ⇒ V= $I\times R_{eq}$

I = 500mA = 500 ×$10^{-3}$ amp. Voltage = 6v

 V= $I\times R_{eq}$

$R_{eq}$ =  $\frac{V}{I}$ = $\frac{6}{500\times 10^{-3} }$ = $\frac{6000}{500}$

$R_{eq}$ = 12 ohm.

Let $R_{Lamp}$ is the resistance of the lamp

The conductor and lamp should be connected in series so

$R_{eq}$ = $R_{Lamp}$ + $R_{conductor}$

12 = $R_{Lamp}$ + 10

$R_{Lamp}$ = 12-10

$R_{Lamp}$ = 2 ohm.

Resistance of the electric lamp= 2 ohm.

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