a current of 5A is flowing at 220V in the primary transformer. if the voltage produced in the secondary coil is 2200V and 50% power is lost, then current in secondary transformer will be
(1)0.25A
(2)0.5A
(3)2.5A
(4)5A
Answers
Answered by
17
Answer:
Vp=220V,
Vs=2200V,
Ip=5A,
Is=?
Power loss = 50% Efficiency of transformer (η)
is defined as the ratio of output power and input power ie,
η50=. ( 2200 × Is / 220 × 5 ) × 100Is
Is = 0.25 A
hope it will help you.....
Answered by
3
Answer:
option (1) is correct..........
0.25A
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