Question

A current of 7A flows through the circuit as shown in the figure. What is the potential difference across B and C.

Answer 1

10 Volts.

Have you read about Null point, then it is the same condition.

No current will flow through the Galvanometer.

So, current flowing through the upper wire = 7A × [15/(6+15)] = 5A

Now, Current through the Series is same, So I = 5 A, for both 4Ω and 2Ω

Potential different across 2Ω resistor (i.e., potential difference across BC) = 2 × 5 = 10 Volts.

Applying Ohms Law, V = IR

Thankyou!!!

Answer 2

Answer:

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Explanation:

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