Question

A current of 80 micro ampere flows in a filament of an x-ray tube. How many electrons are crossing a cross section of filament per second?​

Answer 1

Answer:

5×10^14

Explanation:

I=Q/t =ne/t

Where I=current,Qcharnge

So, here we know I=80microA =80×10^-6A

Charge on an electron=1.6×10^-19C

Therefore, 80×10^-6 = n×1.6×10^-19/1

Or n= 80×10^-6/ 1.6×10^-19

Or n= (800 ×10^19)/(10^6×16)

Or n=8×10^15/16

Or n=0.5×10^15

Or n= 05×10^15 /10

Or《n=5×10^14》 answer

Answer 2

Answer:

5*10^14

Explanation:I=Q/t =ne/t

Where I=current,Qcharnge

So, here we know I=80microA =80×10^-6A

Charge on an electron=1.6×10^-19C

Therefore, 80×10^-6 = n×1.6×10^-19/1

Or n= 80×10^-6/ 1.6×10^-19

Or n= (800 ×10^19)/(10^6×16)

Or n=8×10^15/16

Or n=0.5×10^15

Or n= 05×10^15 /10

Or《n=5×10^14》 answer