Question

A current of 9.65 A is passed for 3 hours between nickel electrodes in .5L of 2M solution of Ni(No3)2.The molarity of the solution after electrolysis would be?

Answer 1

The molarity of the solution after electrolysis would be 0.92 mol.L−1

Explanation:

Given data:

Q = I x t = (9.65 A)(3×60×60 s)

    = 104220 C

Amount of Ni deposited =104220 C / 2× 96500 C mol−1 = 0.54 mol

Amount of Ni2+ left behind = 1 mol - 0.54 mol = 0.46 mol

Molarity of solution =0.46 mol/0.5 L

                                =0.92 mol.L−1

Hence the molarity of the solution after electrolysis would be 0.92 mol.L−1

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