a current of an 1 amphia is drawn by an electrical bulb the numbure of electrons passing throuughthe bulb in 16 second would be
Answers
Answer:
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Explanation:
The relationship between current, charge and time is given as follows.
charge = current x time, that is, Q = It where,
charge is Q, it is measured in coulombs (C)
current is I, it is measured in amperes (A)
time is t, it is measured in seconds (s).
The relationship between electronic charge, charge and number of electrons are protons is given as follows.
charge = number of electrons or protons x electronic charge, that is Q = ne
where,
charge is Q, it is measured in coulombs (C)
number of electrons/protons is n, it is measured in numbers
electronic charge is e, it has a standard value = 1.6×10
−19
Coloumbs (C).
Equating both the above equations, that is,
It = ne we get,n=
e
I×T
=
1.6×10
−19
1×16
=10
20
.
Hence, number of electrons passing through a cross section of the filament in 16 seconds would be roughly 10
20
.
Question:
A current of 1 ampere is drawn by an electrical bulb, the number of electrons passing through the buld in 16 seconds would be?
Answer:
Explanation:
- Current drawn (I) = 1 A
- Time (t) = 16 s
- Number of electrons passing through (q)
→ Charge is given by the equation,
Charge = Current × Time
q = I × t ------equation 1
→ But by the property quantization of charges, we know that
q = ne -------equation 2
where n = number of electrons, e = 1.6 × 10⁻¹⁹C
→ Substitute equation 2 in equation 1
ne = I × t
→ Now substitute the given datas,
n × 1.6 × 10⁻¹⁹ = 1 × 16
n = 16/1.6 × 10⁻¹⁹
n = 10 × 10¹⁹ = 10²⁰ electrons.
→ Basic properties of charges:
- Additivity of charges: The total charge in a system is the sum of all the charges present in that system.
- Conservation of charges: The total charge of an isolated system is always coserve. Charge can neither be created nor be destroyed.
- Quantisation of charges: Electric charge is always an integral multiple of e where e = 1.6 × 10⁻¹⁹C.