A current of o.5 A is drawn by a filament of an electric bulb for half an hour find the amount of electric charge that flows through the circuit
Answers
Answered by
3
We are given, I = 0.5 A; t = 30min = 1800s.
From Eq: I=Q/t
Q = It
0.5×1800
= 900 C
From Eq: I=Q/t
Q = It
0.5×1800
= 900 C
Unnatijalan99:
Thanku maim
Answered by
1
According to physics :-
Current (I) = Electric charge(q) / Time(t)
Hence , q= I ×t
q= 0.5 A × 1800 sec
q = 900 coulomb
Electric charge that flows through the circuit = 900 Coulomb
Hope it helps........Mark it brainliest if possible dear......
Current (I) = Electric charge(q) / Time(t)
Hence , q= I ×t
q= 0.5 A × 1800 sec
q = 900 coulomb
Electric charge that flows through the circuit = 900 Coulomb
Hope it helps........Mark it brainliest if possible dear......
Similar questions