A current of two A is following in a wire of cross section area 2cmsq if the no of free elctron per unit volume is 4 × 10 to the power 28 metercube then calculate the drift velocity
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copper has 8.5 x 10^28 electrons per cubic meter. (a) how many electrons are there in 30 cm length a 12 gauge copper wire (diameter 2.05 mm)? (b) if a current of 1.55 A is flowing in the wire, what is the average drift speed of the electrons along the wire? (There are 6.24 x 10^18 electrons in 1 coulomb of charge.)
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Hii friend,
Here is your answer.......
Given,
I = 2 A
n = 4×10^28 electrons
e = 1.6× 10^-19
Area =2 ×10^-4 m²
Formula:-
I =nA e vd
vd => I/nae
vd => 10^5/1.6 ×4
vd => 10^5/6.4
vd =>0.15625 ×10^5 m/s.
Hope this helps you a little!!!
Here is your answer.......
Given,
I = 2 A
n = 4×10^28 electrons
e = 1.6× 10^-19
Area =2 ×10^-4 m²
Formula:-
I =nA e vd
vd => I/nae
vd => 10^5/1.6 ×4
vd => 10^5/6.4
vd =>0.15625 ×10^5 m/s.
Hope this helps you a little!!!
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