Question

A current strength of 3.86 amp was passed through molten calcium oxide for 41 minutes and 40 seconds. The mass of calcium in grams deposited at the cathode is
(Atomic mass of Ca is 40 g/mol, 1 F = 96500 C)
(a) 4
(b) 2
(c) 6
(d) 8

Answer 1

Use formula

$given mass = i \times t \times molarmass \div 1f \times n$

here n = n factor that is here 2

$take \: t = 3500s$

after putting value u get

$mass \: = 3.86 \times \: 3500 \times 40 \div 96500 \times 2$

$mass = 2.8g$

hence answer may be 2

Answer 2

Answer:

the answer is 2 hope it helps you