Chemistry, asked by rutujasadafule1610, 23 hours ago

A current strength of 5 through silver nitrate solution in an electrolytic cell form 30 minutes. What is the weight of silver deposited at cathode ? (Given ECE of silver is 0.001118)​

Answers

Answered by iemsmahjabinnisha
0

Answer:

Solution

verified

Verified by Toppr

Molar mass of Ag =108 g mol

−1

1 Faraday =96500 C

Q=i×t=1.5 ×5×60=450 Coulombs

Weight of the substance deposited =ZQ

Z=

nF

M

n-factor of AgNO

3

=1

Z=

1×96500

108

Weight of the substance=

96500

108

×450=

9650

54×90

=0.5 g

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