Question

a curve has equation y= x^5 - 8x^3 + 16x. the normal at the point P( 1,9) and the tangent at the point Q( "-1," "-9" ) intersect at point R. find the coordinates of R

Answer 1

Answer:

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Step-by-step explanation:

x+5y = 2

5y = 2 - x

Second curve is

y=2x²-3x-26

5y =10x^2 -15x-130

2-x = 10x^2 -15x-130

10x^2 -14x-132 = 0

5x^2–7x -66 = 0

(5x–22)(x+3) = 0

x =22/5 or

x = 3

y = (2-x)/5

y = 1 or -12/25

So points are

(-3, 1) and (22/5, -12/25) Ans