a curve is given by x=asinϴ,y=bcos2ϴ.find the radius of curvature at ϴ=π/3.
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eq.of circle is
x²+y²=r²
where r is radius
a²sin²ø+b2cos²ø=r²
at ø=π/3
3/4a²+1/4b²=r²
r²=(3a²+b²)/4
r=√(3a²+b²)/2
Hope u understand
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x²+y²=r²
where r is radius
a²sin²ø+b2cos²ø=r²
at ø=π/3
3/4a²+1/4b²=r²
r²=(3a²+b²)/4
r=√(3a²+b²)/2
Hope u understand
Mark it as Brainliest
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