Question

A cycle decreases its speed from 54 km/hr to 36 km/hr in 8 seconds. Find the acceleration of the cycle.​

Answer 1

Answer:

a=v-u /t

a= (36-54)/8

a= 29.25m/s^2

Answer 2

Given :-

• Initial velocity 54km/hr
• Final velocity 36km/hr.
• Time 8seconds

To find :-

• Acceleration

Solution :-

Using formula

${\pink{\underline{\boxed{\bf{\red{Acceleration = \frac{Final \: velocity - initial \: velocity }{Time \: taken} }}}}}}$

By using formula

$:\sf\implies{ \frac{36 - 54}{8} } \\ \\ :\sf\implies{ \frac{ - 18}{8} } \: \: \: \: \: \: \\ \\ :\sf\implies{ - 2.25} \: \: \:$

Answer :

${\large{\blue{\underline{\boxed{\rm{\red{Acceleration = -2.25m/s²}}}}}}}$

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