Question

A cycle heat engine does 50kj of work per cycle. If the efficiency of the heat engine is 75%. The heat rejected per cycle is

Answer 1

Carnot efficiency = Work done/Heat supplied(Q1)

0.75 = 50/ Q1

or, Q1 = 200/3

and, Work done = Q1– Q2

or, Q2 = 200/3-50 = 50/3 = 16.6kJ