Question

a cycle increases its velocity from 10 kmph to 15kmph in 6 sec. calculate its acceleration

Answer 1

$\bf \LARGE \it Hey \: User!!$

according to the question, the cycle increases it's velocity from 10km/h to 15km/h in 6 seconds.

therefore initial velocity = u = 10km/h and final velocity = v = 15km/h

here, time is given in seconds.

so we have to convert velocities in m/s

◾u = 10 × 5/18
= 50/18
= 2.7 m/s

◾v = 15 × 5/18
= 75/18
= 4.16 m/s

we know that acceleration = change in velocity/time
= (v - u)/t
= (4.16 - 2.7)/6
= 1.46/6
= 0.243 m/s²

Cheers!!!

Answer 2

given,
initial velocity (u)=10 km/h
=10000km/3600s = 2.77 km/h
final velocity (v)=15 km/h
=15000km/3600s = km/h
time=4.16s

therefore, acceleration (a)= v - u/t
=4.16 - 2.77/6
=1.39/6
=0.2316 m/s²