Question

A cycle of mass 15 Kg has velocity of 10m/s. After covering the distance of 10m it comes to rest. Find the force of friction between the road and cycle​

Answer 1

Answer:

-750N

Explanation:

Given :

Mass of the cycle = 15kg

Initial velocity of the cycle  = 10m/s

Distance travelled = 10m

Final velocity of the cycle = 0m/s

To Find :

Force  = ?

Solution :

$\sf{}We\ know\ F=ma$

Here F is force applied

m is the mass of the object

a is the acceleration

Acceleration is not given,so let’s find it’s acceleration.

According to the third equation of motion

$\sf{} v^2-u^2=2as$

Here v  is the final velocity.

u is the initial velocity  

a is the acceleration

$\sf{}\implies 0-10^2=2\times a\times 10$

$\sf{}\implies -100=20a$

$\sf{}\implies -\dfrac{100}{20}=a$

$\sf{}\therefore a=-50m/s^2$

Thus force,

$\sf{}\implies Force= 15kg\times -50m/s^2$

$\sf{}\implies Force= -750N$

Therefore,the force of friction between the road and the cycle is -750N