a cycle starting from rest gain a velocity of 54km/h in 10 seconds calculate acceleration as well as distance covered by the cycle
Answers
Explanation:
initial velocity=0
final velocity=54km/hr
=54×5/18=15m/s
time=10s
v=u+at
a=v-u/t
=(15-0)10
=1.5ms^-2
Answer :
➥ The Acceleration of a cycle = 1.5 m/s²
➥ The Distance covered by a cycle = 75 m
Given :
➤ Final velocity of a cycle (v) = 54 km/hr
➤ Time taken by a cycle (t) = 19 sec
To Find :
➤ Acceleration of a cycle (a) = ?
➤ Distance covered by a cycle (s) = ?
Required Solution :
⚡ In the above question given that Intial velocity is 0 km/hr because the cycle is in the rest, final velocity is 54 km/hr, time taken is 10 sec.
☕ To find the acceleration of a cycle and distance covered bt a cycle, first we need to convert the final velocity and Intial velocity of a cycle, then after we will find the Acceleration of a cycle and Distance covered by a cycle.
◈ Intial velocity = 0 km/hr
→ 0 × 18/5
→ 0 m/s
◈ Final velocity = 54 km/hr
→ 54 × 18/5
→ 15 m/s
Now, we have the Intial velocity and Final velocity of a cycle and it's Time taken,
- Intial velocity (u) = 0 m/s
- Final velocity (v) = 15 m/s
- Time taken (t) = 10 sec
We can find Acceleration of a cycle by using the first equation of motion which says v = u + at
☃️ So let's find final velocity (v) !
From first equation of motion
→ v = u + at
→ 15 = 0 + a × 10
→ 15 = 0 + 10a
→ 15 = 10a
→ 15/10 = a
→ 1.5 = a
→ a = 1.5 m/s²
║Hence, the acceleration of a cycle is 1.5 m/s².║
We can find the Distance covered by a cycle by using the second equation of motion which says s = ut + ½ at²,
☃️ So let's find Distance (s) !
From second equation of motion
→ s = ut + ½ at²
→ s = 0 × 10 + ½ × 1.5 × 10²
→ s = 0 + ½ × 1.5 × 100
→ s = 0 + 1 × 1.5 × 50
→ s = 0 + 1.5 × 50
→ s = 0 + 75
→ s = 75 m
║Hence, the distance covered by a cycle is 75 m.║