A CYCLE TOGETHER WITH ITS RIDER WEIGHS 100 KG.HOW MUCH WORK IS NEEDED TO SET IT MOVING AT 3 M/S?
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Answered by
1
Work Done = 1/2mv²
Therefore,
1/2*10*3 = WD
30*1/2 = 15J
So, work done is 15J
Therefore,
1/2*10*3 = WD
30*1/2 = 15J
So, work done is 15J
Answered by
5
450J of energy.
Here work is equal to kinetic energy.
that is 1/2 ×m ×v^2
m is 100 kg
v is 3m/s
If you substitute the values the ans is 450J.
Here work is equal to kinetic energy.
that is 1/2 ×m ×v^2
m is 100 kg
v is 3m/s
If you substitute the values the ans is 450J.
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