Question

A cyclic quadrilateral ABCD in which angle BAD is 75 degree, angle ABD is 58 degree and angle ADC is 77 degree . Find angle BDC and angle BCD​

Answer 1

Answer:

....By angle some property of triangle...

angle ADB =180 degree - 75degree- 58degree=47 degree

#angle BDC = angle ADC- angle ADB=77 degree-47 degree - 47 degree= 30 degree

~~Angle BCD = 180 degree -75 degree = 105 degree