Question

A cyclinder has a height of 14 m and a base of radius 3 m.
Find the curved surface
of
the cylinder​

Answer 1

$\underline{\pink{ Dimensions \: of \: a \: cylinder : }}$

$Height (h) = 14 \: m \:and$

$base \: radius (r) = 3\:m$

$Curved \: surface \:area = 2\pi rh$

$= 2 \times \frac{22}{7} \times 3 \times 14$

$= 2 \times 22 \times 3\times 7$

$= 924 \: m^{2}$

Therefore.,

$\red{Curved \: surface \:area}$

$\green {= 924 \: m^{2}}$

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Answer 2

Explanation :-

Given :-

• Height (h) = 14m
• Radius (r) = 3m

To Find :-

• The curved surface area of cylinder.

Solution :-

As we know that,

Curved surface area = 2πrh.

↪Curved surface area = 2 × 22/7 × 3 × 14

↪Curved surface area = 2 × 22 × 3 × 7

↪Curved surface area = 44 × 21

↪Curved surface area = 924m²

Hence,

• The Curved surface area of cylinder is 924m².