Question

a cyclindrical rod of sliver has a length of 0.7 m and a radius of 0.4m find the density if rod if it's mass is 3700kg
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Answer 1

Solution :-

Given ,

Length or height of rod = 0.7m

Radius of rod = 0.4 m

Mass of rod = 3700 kg

We need to find ,

Density of silver rod

If we need to find the density of silver rod firstly we need to find the volum of rod . Since the rod is in cylindrical shape .

• Volume = πr²h

→ Volume ( rod ) = π × ( 0.4 )² × ( 0.7 )

→ Volume ( rod ) = 3.14 × 0.16 × 0.7

→ Volume of rod = 0.351 m³

Now , finding density of rod using ,

• Density = mass/volume

⇒ Density = 3700/0.351

⇒ Density = 10541.31 kg/m³

Hence , density of silver rod is 10541 kg/m³

Answer 2

Answer:

10,511.36363636

Step-by-step explanation:

h=0.7m

r=0.4m

m=3700kg

volume of cylinder=πr²h

=22/7×0.4×0.4×0.7

0.352

density=mass/volume

=3700kg/0.352

10,511.3636363636