Math, asked by manjotsandhu9494, 2 months ago

A cyclist A started his journey on cycle at 7 :30 a.m at a speed 8 km /hr B , another cyclist , started from the same point half an hour later but with a speed of 10 km / hr At what time did B overtake A ?

Answers

Answered by qazter735

0

Answer:

At 8 a.m cyclist A is 4 km away from cyclist B.

Their relative speed ( B - A) is now 2 km/hr so B meets A after 4 /2 = 2 hours.

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