A cyclist accelerates at a rate of 8.0 m/s^2.How long will it take the cyclist to reach a speed of 18 m/s? (Initial Velocity=0 m/s)
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Given
Initial velocity (u)=0m/s
Speed=18m/s
Acceleration=8m/s^2
To find:time
By using 2nd equation of motion
S=ut+1/2at^2
18=0×t+1/2×8×t^2
18=4×t^2
18/4=t^2
4.5=t^2
t=√4.5
t=2.1 seconds
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Answer:
andy7 Ace
speed = total distance / total time taken
8 km/hr = 21000/t (as distance is given in meter we have to change in kilometer so, 21m = 0.021km
t = 0.021/8
t = 0.02625 hrxplanation:
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