Question

A cyclist acceleratesfrom rest to a velocity of 72km per hour in 10s. the cyclist is in a straight line track. the acceleration of the cyclist is what?

Answer 1

Answer:

Applying 1st law of motion-

v = u + at

u = 36 km/h = 10 m/s, v= 0

0= 10 + 10a , a = -1m/s2, negative acceleration or retardation

3rd law of motion

v2 - u2 = 2as

0 - 100 = 2*-1*s

-100/-2 = s

s = 50 m.

And that is the answer.

Distance travelled = 50m,

Negative acceleration of -1m/s2.

Explanation:

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