Question

a cyclist after cycling a distance of 70 kilometre on the second day find that the ratio of distances covered by him on the first two day is 4 : 5. if he travels a distance of 42 km on the third day, then the ratio of distance travelled on the third day and the first day is​

Answer 1

let distance be x

then x/70 = 4/5

x=56

lets find ratio of 42 and 56

42/ 56 = 3/4

Answer 2

The ratio of distance travelled on the third day and the first day is​ 3:4.

Explanation:

Let x be the distance traveled on first day.

As per given :

Distance traveled on the second day = 70 kilometer

ratio of distances covered by him on the first two day is 4 : 5.

i.e. $\dfrac{x}{70}=\dfrac{4}{5}\Rightarrow\ x=\dfrac{4}{5}\times70=56$

i.e. Distance traveled on the first day = 56 km

if he travels a distance of 42 km on the third day, then the ratio of distance travelled on the third day and the first day would be $\dfrac{42}{56}=\dfrac{3}{4}$ =3:4.

Hence, the ratio of distance travelled on the third day and the first day is​ 3:4.

# Learn more :

The ratio of the radii of the two circle is 3.5 find the ratio of the circumference also find the ratio of the areas

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