Question

. A cyclist and a person on a moped are acted upon by the same force. If the acceleration produced by the cyclist is only 2/5th that of the moped, calculate the ratio of the massesof to he cyclist and the moped​

Answer 1

The centripetal force acting on the bicycle is given by,

F

c

=

r

mv

2

=

100

100×10×10

=100N

Required frictional force to cross the turn,

F

f

=μmg

=0.6×100×10=600N

As the frictional force is greater than the centripetal force, so the rider will be able to cross the turn.

Answer 2

Answer:

Ok good night sweet dreams