Question

A cyclist at 5 second pick velocity of 10 metre second over a distance of 50 metre calculate1
acleration second time

Answer 1

For the cyclist;

time elapsed (t) = 5 s

initial velocity (u) = 0 m/s

final velocity (v) = 10 s

distance (s) = 50 m

acceleration (a)

$= \frac{v - u}{t} = \frac{10 - 0}{5} = \frac{10}{5} \\ = 2 \: m {s}^{ - 2}$

Hence, acceleration of the cyclist was 2 m/s².