Question

A cyclist comes to a skidding stop in 10m. During this process, the force on the cycle due to the road is 200N and is directly opposed to the motion. (a) How much work does the road do on the cycle? (b) How much work does the cycle do on the road?

Answer 1

work= F ×s

work=200×10

work=2000J

please follow me

Answer 2

$\huge {\boxed {\mathbb{QUESTION}}}$

A cyclist comes to a skidding stop in 10m. During this process, the force on the cycle due to the road is 200N and is directly opposed to the motion. (a) How much work does the road do on the cycle? (b) How much work does the cycle do on the road?

$\huge {\boxed {\mathbb{ANSWER}}}$

${\boxed {\mathbb{GIVEN}}}$

• $Distance(D) =10m$
• $Force(F) =200N$

${\boxed {\mathbb{TO\:PROVE}}}$

• $(a)\: How\: much\: work\: does\: the\: road\:\\ do\: on\: the\: cycle$
• $(b) \:How \:much \:work \:does\: the\: cycle\:\\ do\: on \:the \:road$

$\huge {\boxed {\mathbb{SOLUTION}}}$

$\huge {(a)}$

${\boxed{\boxed {W=FD}}}$

• $W=work\:done$
• $F=force$
• $D=distance$

$Substitute \:the\:values$

$\implies - 10\times 200$

$\implies {\boxed{\boxed {-2000J}}}$

_______________________________________

$\huge {(b)}$

${\boxed{\boxed {W=FD}}}$

• $W=work\:done$
• $F=force$
• $D=distance$

$Substitute \:the\:values$

$\implies 10\times 200$

$\implies {\boxed{\boxed {2000J}}}$

$\huge {\boxed {\mathbb{HOPE \:IT \:HELPS \:YOU }}}$

___________________________________

$\huge {\boxed {\mathbb{EXTRA\:INFORMATION}}}$

$Force(F) =\frac{W} {D}$

$Distance (D) =\frac{W} {F}$

___________________________________

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5070}}}}}}}}}}}}}}}$