Question

A cyclist complete half round of a circular track of a diameter 636 m find his velocity

Answer 1

Explanation:

Radius of the circular track is 318 m

The time elapsed in the journey is 1.5 min or 90 s

The distance traveled by the cyclist is semi circumference of the circle = πr

The displacement of the cyclist will be shortest distance from his initial to final positions which is nothing but diameter of the circle = 2r

We know that

Speed = Distance covered / Time taken

= 318 *3.14 m/90s = 11 m/s

Speed of the cyclist is 11 m/s

Velocity = Displacement / Time

= 2*318 m /90 s = 7 m/s

Velocity of the cyclist is 7 m/s