Question

A cyclist completed half round of a circlar track of radius 318m in 1.5 minutes. find its
velocity​

Answer 1

answer :

the velocity of cyclist is 7.06 m per sec.

Explanation:

Radius of track = 318 m

time taken = 1.5 min = 90 sec

Now,

$velocity(v) = \frac{displacement(s)}{time(t)}$

since , cyclist complete half round his displacement will be Equal to diameter of track

s = 2r

s = 2 × 318 m

s = 636 m

t = 90 sec

$v = \frac{636 \: m}{90 \: sec}$

$v = 7.06 \: m \: per \: sec$

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