Physics, asked by thereisnoname, 5 hours ago

a cyclist completes one round of a circular track of diameter 300 m in 50 s. what will be the distance covered and the displacement at the end of 2 min 30 sec​

Answers

Answered by jharagini00183
2

Answer:Given parameters

The diameter of the circular track = 200 m

Radius (r) = 200/2

r = 100 m

Time is taken by an athlete to complete one round = 40 seconds.

Displacement = ??

Speed = Distance/Time

Total time athlete moves – 2 min 20 seconds

2 min 20 seconds =  2 × 60 + 20

2 min 20 seconds = 140 seconds

Need to find the distance covered in one round

Distance covered in one round = Circumference of circle

Distance covered in one round = 2πr

Distance covered in one round = 2

Distance covered in one round = 2 × 100π

Distance covered in one round =200π

Time is taken by an athlete to complete one round = 40 seconds.

Number of rounds completed in 140s = 140/40

Number of rounds completed in 140s = 35

Distance covered = 3.5 × circumference

Distance covered = 3.5 × 2πr

Distance covered = 3.5 × 2 × 3.14 × 100

Distance covered = 2200 m

Hence, the distance covered at the end of 2 min 20 seconds is 2200 m or 22 km.

And displacement is 200 m as it returns to the initial position.

Explanation:

Answered by chinMaya007
1

Answer:

It says that he makes one round which means we have to find the circumference.

300 ÷ 2 = 150

Circumference = 2πr

= 2 × 3.14 × 150

= 942

if he takes 50 seconds to run 942m^2

Then,

2min, 30 seconds has 3 50's

942 × 3

= 2826

Therefore 2826m^2 is the total distance he covered in 2 min, 30 seconds

Hope this helps you...

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