Question

a cyclist covers a distance of 4km 200m in 20mins had he increased by 30m per mins . how much time could he have saved​

Answer 1

Answer:

Given :-

distance =4km 200m =4×1000+200

=4200 m

time =20min =20×60

=1200sec

so,speed =distance /time

=4200/1200

=21/6 m/s

A/Q

Speed is increased by 30m/s

And,distance =4200m/s

time=?

time =distance /speed

=4200/30

=140s

time was saved =1200s-140s

=1060s